答案解析

查看更多优质解析解答一举报A(x1,

y1),

B(x2,

y2),

AB的中点M( (x1+x2)/2,

(y1+y2)/2)AB的斜率:k=(y2-y1)/(x2-x1)AB的垂直平分线的斜率为:-1/k因此由点斜式写出AB垂直平分线:y=-(x2-x1/(y2-y1)* [x-(x1+x2)/2]+(y1+y2)/2

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