答案解析
查看更多优质解析解答一举报A(x1,
y1),
B(x2,
y2),
AB的中点M( (x1+x2)/2,
(y1+y2)/2)AB的斜率:k=(y2-y1)/(x2-x1)AB的垂直平分线的斜率为:-1/k因此由点斜式写出AB垂直平分线:y=-(x2-x1/(y2-y1)* [x-(x1+x2)/2]+(y1+y2)/2
更多推荐
查看更多优质解析解答一举报A(x1,
y1),
B(x2,
y2),
AB的中点M( (x1+x2)/2,
(y1+y2)/2)AB的斜率:k=(y2-y1)/(x2-x1)AB的垂直平分线的斜率为:-1/k因此由点斜式写出AB垂直平分线:y=-(x2-x1/(y2-y1)* [x-(x1+x2)/2]+(y1+y2)/2
更多推荐
发布评论